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5354413330037 is a prime number
BaseRepresentation
bin100110111101010101111…
…1001111000111001110101
3200221212200021022201110012
41031322223321320321311
51200211314303030122
615215441124110005
71061562232234622
oct115725371707165
920855607281405
105354413330037
111784880810002
1272587a235305
132cabc40b2085
14147225403349
1594431e437e2
hex4deabe78e75

5354413330037 has 2 divisors, whose sum is σ = 5354413330038. Its totient is φ = 5354413330036.

The previous prime is 5354413330033. The next prime is 5354413330061. The reversal of 5354413330037 is 7300333144535.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 4746498393316 + 607914936721 = 2178646^2 + 779689^2 .

It is a cyclic number.

It is not a de Polignac number, because 5354413330037 - 22 = 5354413330033 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 5354413329976 and 5354413330003.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5354413330033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2677206665018 + 2677206665019.

It is an arithmetic number, because the mean of its divisors is an integer number (2677206665019).

Almost surely, 25354413330037 is an apocalyptic number.

It is an amenable number.

5354413330037 is a deficient number, since it is larger than the sum of its proper divisors (1).

5354413330037 is an equidigital number, since it uses as much as digits as its factorization.

5354413330037 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 680400, while the sum is 41.

The spelling of 5354413330037 in words is "five trillion, three hundred fifty-four billion, four hundred thirteen million, three hundred thirty thousand, thirty-seven".