Base | Representation |
---|---|
bin | 11000010110100010111000… |
… | …10000010111100001110101 |
3 | 21000121110000012112211100011 |
4 | 30023101130100113201311 |
5 | 24004340324202303302 |
6 | 305521025350420221 |
7 | 14164642441626424 |
oct | 1413213420274165 |
9 | 230543005484304 |
10 | 53551200041077 |
11 | 16076a333899a2 |
12 | 600a6b8661671 |
13 | 23b5b1994a72b |
14 | d31c6b5952bb |
15 | 62cec9dc45d7 |
hex | 30b45c417875 |
53551200041077 has 2 divisors, whose sum is σ = 53551200041078. Its totient is φ = 53551200041076.
The previous prime is 53551200041041. The next prime is 53551200041081. The reversal of 53551200041077 is 77014000215535.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 44450835785316 + 9100364255761 = 6667146^2 + 3016681^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-53551200041077 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53551200047077) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26775600020538 + 26775600020539.
It is an arithmetic number, because the mean of its divisors is an integer number (26775600020539).
Almost surely, 253551200041077 is an apocalyptic number.
It is an amenable number.
53551200041077 is a deficient number, since it is larger than the sum of its proper divisors (1).
53551200041077 is an equidigital number, since it uses as much as digits as its factorization.
53551200041077 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 147000, while the sum is 40.
The spelling of 53551200041077 in words is "fifty-three trillion, five hundred fifty-one billion, two hundred million, forty-one thousand, seventy-seven".
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