Base | Representation |
---|---|
bin | 100110111101110011101… |
… | …1100010110100011000101 |
3 | 200221222020212220121000111 |
4 | 1031323213130112203011 |
5 | 1200220341012020401 |
6 | 15220124205513021 |
7 | 1061626051533556 |
oct | 115734734264305 |
9 | 20858225817014 |
10 | 5355412220101 |
11 | 1785243645989 |
12 | 725ab8872771 |
13 | 2cb023020c98 |
14 | 1472bbd4232d |
15 | 9448e9a5e51 |
hex | 4dee77168c5 |
5355412220101 has 2 divisors, whose sum is σ = 5355412220102. Its totient is φ = 5355412220100.
The previous prime is 5355412220069. The next prime is 5355412220113. The reversal of 5355412220101 is 1010222145535.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 5173923439876 + 181488780225 = 2274626^2 + 426015^2 .
It is a cyclic number.
It is not a de Polignac number, because 5355412220101 - 25 = 5355412220069 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5355412220401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2677706110050 + 2677706110051.
It is an arithmetic number, because the mean of its divisors is an integer number (2677706110051).
Almost surely, 25355412220101 is an apocalyptic number.
It is an amenable number.
5355412220101 is a deficient number, since it is larger than the sum of its proper divisors (1).
5355412220101 is an equidigital number, since it uses as much as digits as its factorization.
5355412220101 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12000, while the sum is 31.
Adding to 5355412220101 its reverse (1010222145535), we get a palindrome (6365634365636).
The spelling of 5355412220101 in words is "five trillion, three hundred fifty-five billion, four hundred twelve million, two hundred twenty thousand, one hundred one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.084 sec. • engine limits •