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5355856289131 is a prime number
BaseRepresentation
bin100110111110000000111…
…1010010101110101101011
3200222000101211111122012121
41031330001322111311223
51200222243202223011
615220240231452111
71061643053211505
oct115740172256553
920860354448177
105355856289131
111785451280587
12726001527037
132cb09402221a
14147320cd8d75
15944b8971e71
hex4df01e95d6b

5355856289131 has 2 divisors, whose sum is σ = 5355856289132. Its totient is φ = 5355856289130.

The previous prime is 5355856289129. The next prime is 5355856289237. The reversal of 5355856289131 is 1319826585535.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 5355856289131 - 21 = 5355856289129 is a prime.

It is a super-3 number, since 3×53558562891313 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 5355856289129, it forms a pair of twin primes.

It is a self number, because there is not a number n which added to its sum of digits gives 5355856289131.

It is not a weakly prime, because it can be changed into another prime (5355856289431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2677928144565 + 2677928144566.

It is an arithmetic number, because the mean of its divisors is an integer number (2677928144566).

Almost surely, 25355856289131 is an apocalyptic number.

5355856289131 is a deficient number, since it is larger than the sum of its proper divisors (1).

5355856289131 is an equidigital number, since it uses as much as digits as its factorization.

5355856289131 is an evil number, because the sum of its binary digits is even.

The product of its digits is 38880000, while the sum is 61.

The spelling of 5355856289131 in words is "five trillion, three hundred fifty-five billion, eight hundred fifty-six million, two hundred eighty-nine thousand, one hundred thirty-one".