Base | Representation |
---|---|
bin | 1001111110100010… |
… | …00100111010010111 |
3 | 111211022000202001221 |
4 | 10333101010322113 |
5 | 41432220032341 |
6 | 2243302231211 |
7 | 246510502141 |
oct | 47721047227 |
9 | 14738022057 |
10 | 5356408471 |
11 | 22a9609a67 |
12 | 1055a25507 |
13 | 67494998b |
14 | 38b559c91 |
15 | 2153a8ed1 |
hex | 13f444e97 |
5356408471 has 2 divisors, whose sum is σ = 5356408472. Its totient is φ = 5356408470.
The previous prime is 5356408457. The next prime is 5356408511. The reversal of 5356408471 is 1748046535.
5356408471 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5356408471 - 211 = 5356406423 is a prime.
It is a super-3 number, since 3×53564084713 (a number of 30 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5356408411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2678204235 + 2678204236.
It is an arithmetic number, because the mean of its divisors is an integer number (2678204236).
Almost surely, 25356408471 is an apocalyptic number.
5356408471 is a deficient number, since it is larger than the sum of its proper divisors (1).
5356408471 is an equidigital number, since it uses as much as digits as its factorization.
5356408471 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 403200, while the sum is 43.
The square root of 5356408471 is about 73187.4884867625. The cubic root of 5356408471 is about 1749.6770528964.
The spelling of 5356408471 in words is "five billion, three hundred fifty-six million, four hundred eight thousand, four hundred seventy-one".
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