Base | Representation |
---|---|
bin | 10100011100110110000101 |
3 | 101002100221122 |
4 | 110130312011 |
5 | 2333023104 |
6 | 310523325 |
7 | 63365552 |
oct | 24346605 |
9 | 11070848 |
10 | 5361029 |
11 | 3031903 |
12 | 1966545 |
13 | 115920b |
14 | 9d7a29 |
15 | 70d6be |
hex | 51cd85 |
5361029 has 2 divisors, whose sum is σ = 5361030. Its totient is φ = 5361028.
The previous prime is 5361023. The next prime is 5361043. The reversal of 5361029 is 9201635.
5361029 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4972900 + 388129 = 2230^2 + 623^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5361029 is a prime.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 5360989 and 5361007.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5361023) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2680514 + 2680515.
It is an arithmetic number, because the mean of its divisors is an integer number (2680515).
Almost surely, 25361029 is an apocalyptic number.
It is an amenable number.
5361029 is a deficient number, since it is larger than the sum of its proper divisors (1).
5361029 is an equidigital number, since it uses as much as digits as its factorization.
5361029 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1620, while the sum is 26.
The square root of 5361029 is about 2315.3896000457. The cubic root of 5361029 is about 175.0180008694.
Subtracting 5361029 from its reverse (9201635), we obtain a triangular number (3840606 = T2771).
The spelling of 5361029 in words is "five million, three hundred sixty-one thousand, twenty-nine".
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