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53613731341 is a prime number
BaseRepresentation
bin110001111011101000…
…001001111000001101
312010101102200202002101
4301323220021320031
51334300103400331
640344012155101
73605412124432
oct617350117015
9163342622071
1053613731341
112081260a985
12a483168a91
135095649bb1
142848655b89
1515dbc6a061
hexc7ba09e0d

53613731341 has 2 divisors, whose sum is σ = 53613731342. Its totient is φ = 53613731340.

The previous prime is 53613731321. The next prime is 53613731359. The reversal of 53613731341 is 14313731635.

53613731341 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 53215569225 + 398162116 = 230685^2 + 19954^2 .

It is a cyclic number.

It is not a de Polignac number, because 53613731341 - 217 = 53613600269 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 53613731341.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (53613731321) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26806865670 + 26806865671.

It is an arithmetic number, because the mean of its divisors is an integer number (26806865671).

Almost surely, 253613731341 is an apocalyptic number.

It is an amenable number.

53613731341 is a deficient number, since it is larger than the sum of its proper divisors (1).

53613731341 is an equidigital number, since it uses as much as digits as its factorization.

53613731341 is an evil number, because the sum of its binary digits is even.

The product of its digits is 68040, while the sum is 37.

The spelling of 53613731341 in words is "fifty-three billion, six hundred thirteen million, seven hundred thirty-one thousand, three hundred forty-one".