Base | Representation |
---|---|
bin | 1111100110101010000… |
… | …01100010011110111101 |
3 | 1220020220012121122201021 |
4 | 13303111001202132331 |
5 | 32241013333120401 |
6 | 1050145344544141 |
7 | 53510202625462 |
oct | 7632501423675 |
9 | 1806805548637 |
10 | 536149895101 |
11 | 19741a702767 |
12 | 87aab622051 |
13 | 3b735671b52 |
14 | 1bd42339669 |
15 | de2e6032a1 |
hex | 7cd50627bd |
536149895101 has 2 divisors, whose sum is σ = 536149895102. Its totient is φ = 536149895100.
The previous prime is 536149895077. The next prime is 536149895143. The reversal of 536149895101 is 101598941635.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 445554915001 + 90594980100 = 667499^2 + 300990^2 .
It is a cyclic number.
It is not a de Polignac number, because 536149895101 - 221 = 536147797949 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (536149895191) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 268074947550 + 268074947551.
It is an arithmetic number, because the mean of its divisors is an integer number (268074947551).
Almost surely, 2536149895101 is an apocalyptic number.
It is an amenable number.
536149895101 is a deficient number, since it is larger than the sum of its proper divisors (1).
536149895101 is an equidigital number, since it uses as much as digits as its factorization.
536149895101 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1166400, while the sum is 52.
The spelling of 536149895101 in words is "five hundred thirty-six billion, one hundred forty-nine million, eight hundred ninety-five thousand, one hundred one".
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