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5362500103 = 11941449083
BaseRepresentation
bin1001111111010000…
…10100001000000111
3111211201111020012221
410333220110020013
541440300000403
62244040553211
7246613333042
oct47750241007
914751436187
105362500103
112301a9a774
121057a82807
13675ca05ac
1438c2a3c59
15215baddbd
hex13fa14207

5362500103 has 4 divisors (see below), whose sum is σ = 5362961128. Its totient is φ = 5362039080.

The previous prime is 5362500083. The next prime is 5362500119. The reversal of 5362500103 is 3010052635.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 5362500103 - 229 = 4825629191 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5362500133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 212601 + ... + 236482.

It is an arithmetic number, because the mean of its divisors is an integer number (1340740282).

Almost surely, 25362500103 is an apocalyptic number.

5362500103 is a deficient number, since it is larger than the sum of its proper divisors (461025).

5362500103 is a wasteful number, since it uses less digits than its factorization.

5362500103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 461024.

The product of its (nonzero) digits is 2700, while the sum is 25.

The square root of 5362500103 is about 73229.0932826564. The cubic root of 5362500103 is about 1750.3400811723.

Adding to 5362500103 its reverse (3010052635), we get a palindrome (8372552738).

The spelling of 5362500103 in words is "five billion, three hundred sixty-two million, five hundred thousand, one hundred three".

Divisors: 1 11941 449083 5362500103