Base | Representation |
---|---|
bin | 100111000001011110110… |
… | …0110000000001001010111 |
3 | 200222201121121020102112111 |
4 | 1032002331212000021113 |
5 | 1200333014302310203 |
6 | 15223511021131451 |
7 | 1062325401106051 |
oct | 116027546001127 |
9 | 20881547212474 |
10 | 5363300041303 |
11 | 1788621063786 |
12 | 72753a3b9b87 |
13 | 2cb9ac2480c9 |
14 | 1478297688d1 |
15 | 947a21e326d |
hex | 4e0bd980257 |
5363300041303 has 2 divisors, whose sum is σ = 5363300041304. Its totient is φ = 5363300041302.
The previous prime is 5363300041243. The next prime is 5363300041357. The reversal of 5363300041303 is 3031400033635.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5363300041303 - 225 = 5363266486871 is a prime.
It is a super-3 number, since 3×53633000413033 (a number of 39 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5363300041103) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2681650020651 + 2681650020652.
It is an arithmetic number, because the mean of its divisors is an integer number (2681650020652).
Almost surely, 25363300041303 is an apocalyptic number.
5363300041303 is a deficient number, since it is larger than the sum of its proper divisors (1).
5363300041303 is an equidigital number, since it uses as much as digits as its factorization.
5363300041303 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 29160, while the sum is 31.
Adding to 5363300041303 its reverse (3031400033635), we get a palindrome (8394700074938).
The spelling of 5363300041303 in words is "five trillion, three hundred sixty-three billion, three hundred million, forty-one thousand, three hundred three".
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