Base | Representation |
---|---|
bin | 111100111110111011001110… |
… | …1010011110010011101111101 |
3 | 2121100021200021020111012201201 |
4 | 1321331312131103302131331 |
5 | 1030302101322331202233 |
6 | 5140505103540135501 |
7 | 220662426502466044 |
oct | 17175663523623575 |
9 | 2540250236435651 |
10 | 536413989709693 |
11 | 145a109939a8617 |
12 | 501b475b997591 |
13 | 1a040811c19194 |
14 | 966680b75355b |
15 | 420355b30777d |
hex | 1e7dd9d4f277d |
536413989709693 has 2 divisors, whose sum is σ = 536413989709694. Its totient is φ = 536413989709692.
The previous prime is 536413989709603. The next prime is 536413989709699. The reversal of 536413989709693 is 396907989314635.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 427168786835844 + 109245202873849 = 20668062^2 + 10452043^2 .
It is a cyclic number.
It is not a de Polignac number, because 536413989709693 - 213 = 536413989701501 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (536413989709699) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 268206994854846 + 268206994854847.
It is an arithmetic number, because the mean of its divisors is an integer number (268206994854847).
Almost surely, 2536413989709693 is an apocalyptic number.
It is an amenable number.
536413989709693 is a deficient number, since it is larger than the sum of its proper divisors (1).
536413989709693 is an equidigital number, since it uses as much as digits as its factorization.
536413989709693 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7142567040, while the sum is 82.
The spelling of 536413989709693 in words is "five hundred thirty-six trillion, four hundred thirteen billion, nine hundred eighty-nine million, seven hundred nine thousand, six hundred ninety-three".
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