Base | Representation |
---|---|
bin | 100111000001111010010… |
… | …1110101010110100010001 |
3 | 200222211000001211020210102 |
4 | 1032003310232222310101 |
5 | 1200341413103410423 |
6 | 15224142503342145 |
7 | 1062360332455643 |
oct | 116036456526421 |
9 | 20884001736712 |
10 | 5364225060113 |
11 | 1788a56224037 |
12 | 727758151955 |
13 | 2cbac8a9140a |
14 | 1478b6558893 |
15 | 94808512c28 |
hex | 4e0f4baad11 |
5364225060113 has 2 divisors, whose sum is σ = 5364225060114. Its totient is φ = 5364225060112.
The previous prime is 5364225060071. The next prime is 5364225060157. The reversal of 5364225060113 is 3110605224635.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4023325907329 + 1340899152784 = 2005823^2 + 1157972^2 .
It is a cyclic number.
It is not a de Polignac number, because 5364225060113 - 214 = 5364225043729 is a prime.
It is not a weakly prime, because it can be changed into another prime (5364225060163) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2682112530056 + 2682112530057.
It is an arithmetic number, because the mean of its divisors is an integer number (2682112530057).
Almost surely, 25364225060113 is an apocalyptic number.
It is an amenable number.
5364225060113 is a deficient number, since it is larger than the sum of its proper divisors (1).
5364225060113 is an equidigital number, since it uses as much as digits as its factorization.
5364225060113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 129600, while the sum is 38.
The spelling of 5364225060113 in words is "five trillion, three hundred sixty-four billion, two hundred twenty-five million, sixty thousand, one hundred thirteen".
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