Base | Representation |
---|---|
bin | 100111000001111101110… |
… | …1010100011110001101101 |
3 | 200222211022011210002221212 |
4 | 1032003323222203301231 |
5 | 1200342132401020323 |
6 | 15224202221404205 |
7 | 1062363244521653 |
oct | 116037352436155 |
9 | 20884264702855 |
10 | 5364341423213 |
11 | 1789005981393 |
12 | 72778b109665 |
13 | 2cbb16c13b16 |
14 | 1478c7ba8dd3 |
15 | 9481384ab78 |
hex | 4e0fbaa3c6d |
5364341423213 has 2 divisors, whose sum is σ = 5364341423214. Its totient is φ = 5364341423212.
The previous prime is 5364341423171. The next prime is 5364341423257. The reversal of 5364341423213 is 3123241434635.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3058626725449 + 2305714697764 = 1748893^2 + 1518458^2 .
It is a cyclic number.
It is not a de Polignac number, because 5364341423213 - 232 = 5360046455917 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5364341423293) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2682170711606 + 2682170711607.
It is an arithmetic number, because the mean of its divisors is an integer number (2682170711607).
Almost surely, 25364341423213 is an apocalyptic number.
It is an amenable number.
5364341423213 is a deficient number, since it is larger than the sum of its proper divisors (1).
5364341423213 is an equidigital number, since it uses as much as digits as its factorization.
5364341423213 is an evil number, because the sum of its binary digits is even.
The product of its digits is 622080, while the sum is 41.
Adding to 5364341423213 its reverse (3123241434635), we get a palindrome (8487582857848).
The spelling of 5364341423213 in words is "five trillion, three hundred sixty-four billion, three hundred forty-one million, four hundred twenty-three thousand, two hundred thirteen".
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