Base | Representation |
---|---|
bin | 11000011001010001001100… |
… | …10110000110101010111111 |
3 | 21000221101120021212222201001 |
4 | 30030220212112012222333 |
5 | 24012404004410340433 |
6 | 310032023550031131 |
7 | 14204464530500614 |
oct | 1414504626065277 |
9 | 230841507788631 |
10 | 53644784855743 |
11 | 16102697597334 |
12 | 6024875aa84a7 |
13 | 23c18b2364003 |
14 | d365c860c50b |
15 | 630655d1357d |
hex | 30ca26586abf |
53644784855743 has 2 divisors, whose sum is σ = 53644784855744. Its totient is φ = 53644784855742.
The previous prime is 53644784855659. The next prime is 53644784855777. The reversal of 53644784855743 is 34755848744635.
53644784855743 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 53644784855743 - 213 = 53644784847551 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53644784855443) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26822392427871 + 26822392427872.
It is an arithmetic number, because the mean of its divisors is an integer number (26822392427872).
Almost surely, 253644784855743 is an apocalyptic number.
53644784855743 is a deficient number, since it is larger than the sum of its proper divisors (1).
53644784855743 is an equidigital number, since it uses as much as digits as its factorization.
53644784855743 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 5419008000, while the sum is 73.
The spelling of 53644784855743 in words is "fifty-three trillion, six hundred forty-four billion, seven hundred eighty-four million, eight hundred fifty-five thousand, seven hundred forty-three".
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