Base | Representation |
---|---|
bin | 1111100111100000001… |
… | …11011000000111100101 |
3 | 1220022001212212102102001 |
4 | 13303300013120013211 |
5 | 32242431212112331 |
6 | 1050302422445301 |
7 | 53524362142006 |
oct | 7636007300745 |
9 | 1808055772361 |
10 | 536604410341 |
11 | 19763322279a |
12 | 87bb7893831 |
13 | 3b7a888ca8c |
14 | 1bd868511ad |
15 | de59484561 |
hex | 7cf01d81e5 |
536604410341 has 2 divisors, whose sum is σ = 536604410342. Its totient is φ = 536604410340.
The previous prime is 536604410317. The next prime is 536604410347. The reversal of 536604410341 is 143014406635.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 408186821025 + 128417589316 = 638895^2 + 358354^2 .
It is a cyclic number.
It is not a de Polignac number, because 536604410341 - 231 = 534456926693 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 536604410341.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (536604410347) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 268302205170 + 268302205171.
It is an arithmetic number, because the mean of its divisors is an integer number (268302205171).
Almost surely, 2536604410341 is an apocalyptic number.
It is an amenable number.
536604410341 is a deficient number, since it is larger than the sum of its proper divisors (1).
536604410341 is an equidigital number, since it uses as much as digits as its factorization.
536604410341 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 103680, while the sum is 37.
Adding to 536604410341 its reverse (143014406635), we get a palindrome (679618816976).
The spelling of 536604410341 in words is "five hundred thirty-six billion, six hundred four million, four hundred ten thousand, three hundred forty-one".
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