Base | Representation |
---|---|
bin | 1100110010110… |
… | …1110010001011 |
3 | 10201222110102011 |
4 | 3030231302023 |
5 | 102214234112 |
6 | 5154120351 |
7 | 1221100312 |
oct | 314556213 |
9 | 121873364 |
10 | 53664907 |
11 | 2832426a |
12 | 15b800b7 |
13 | b16c5aa |
14 | 71ad279 |
15 | 4aa0aa7 |
hex | 332dc8b |
53664907 has 2 divisors, whose sum is σ = 53664908. Its totient is φ = 53664906.
The previous prime is 53664901. The next prime is 53664913. The reversal of 53664907 is 70946635.
It is a balanced prime because it is at equal distance from previous prime (53664901) and next prime (53664913).
It is a cyclic number.
It is not a de Polignac number, because 53664907 - 23 = 53664899 is a prime.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 53664907.
It is not a weakly prime, because it can be changed into another prime (53664901) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26832453 + 26832454.
It is an arithmetic number, because the mean of its divisors is an integer number (26832454).
Almost surely, 253664907 is an apocalyptic number.
53664907 is a deficient number, since it is larger than the sum of its proper divisors (1).
53664907 is an equidigital number, since it uses as much as digits as its factorization.
53664907 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 136080, while the sum is 40.
The square root of 53664907 is about 7325.6335562189. The cubic root of 53664907 is about 377.1928574896.
The spelling of 53664907 in words is "fifty-three million, six hundred sixty-four thousand, nine hundred seven".
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