Base | Representation |
---|---|
bin | 110001111110101111… |
… | …001111010000010001 |
3 | 12010112001220012111022 |
4 | 301332233033100101 |
5 | 1334401433420032 |
6 | 40353114525225 |
7 | 3606614536133 |
oct | 617657172021 |
9 | 163461805438 |
10 | 53665920017 |
11 | 2083a016016 |
12 | a498736815 |
13 | 50a33c0578 |
14 | 285155d053 |
15 | 15e1628512 |
hex | c7ebcf411 |
53665920017 has 2 divisors, whose sum is σ = 53665920018. Its totient is φ = 53665920016.
The previous prime is 53665919981. The next prime is 53665920019. The reversal of 53665920017 is 71002956635.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 29353626241 + 24312293776 = 171329^2 + 155924^2 .
It is a cyclic number.
It is not a de Polignac number, because 53665920017 - 220 = 53664871441 is a prime.
Together with 53665920019, it forms a pair of twin primes.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 53665920017.
It is not a weakly prime, because it can be changed into another prime (53665920019) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26832960008 + 26832960009.
It is an arithmetic number, because the mean of its divisors is an integer number (26832960009).
Almost surely, 253665920017 is an apocalyptic number.
It is an amenable number.
53665920017 is a deficient number, since it is larger than the sum of its proper divisors (1).
53665920017 is an equidigital number, since it uses as much as digits as its factorization.
53665920017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 340200, while the sum is 44.
The spelling of 53665920017 in words is "fifty-three billion, six hundred sixty-five million, nine hundred twenty thousand, seventeen".
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