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5367398400000 = 2213255713
BaseRepresentation
bin100111000011011000111…
…1000000000000000000000
3201000010012020000121202100
41032012301320000000000
51200414412442300000
615225425423150400
71062532064430510
oct116066170000000
921003166017670
105367398400000
11178a33451828a
127282a2a45400
132cc1b3357220
14147ad7ba3840
1594941de6a00
hex4e1b1e00000

5367398400000 has 1584 divisors, whose sum is σ = 23853571586208. Its totient is φ = 1132462080000.

The previous prime is 5367398399971. The next prime is 5367398400041. The reversal of 5367398400000 is 48937635.

5367398400000 is a `hidden beast` number, since 536 + 7 + 39 + 84 + 0 + 0 + 0 + 0 + 0 = 666.

It is a Harshad number since it is a multiple of its sum of digits (45).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 412876799994 + ... + 412876800006.

Almost surely, 25367398400000 is an apocalyptic number.

5367398400000 is a gapful number since it is divisible by the number (50) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 5367398400000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (11926785793104).

5367398400000 is an abundant number, since it is smaller than the sum of its proper divisors (18486173186208).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

5367398400000 is an frugal number, since it uses more digits than its factorization.

5367398400000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 93 (or 30 counting only the distinct ones).

The product of its (nonzero) digits is 544320, while the sum is 45.

The spelling of 5367398400000 in words is "five trillion, three hundred sixty-seven billion, three hundred ninety-eight million, four hundred thousand".