Search a number
-
+
536992697741 is a prime number
BaseRepresentation
bin1111101000001110100…
…00100100110110001101
31220100001221111110120212
413310013100210312031
532244230112311431
61050405133052205
753540115422153
oct7640720446615
91810057443525
10536992697741
11197812418875
12880a5927065
133b83b160136
141bdc22473d3
15de7d5d272b
hex7d07424d8d

536992697741 has 2 divisors, whose sum is σ = 536992697742. Its totient is φ = 536992697740.

The previous prime is 536992697687. The next prime is 536992697771. The reversal of 536992697741 is 147796299635.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 415578779716 + 121413918025 = 644654^2 + 348445^2 .

It is a cyclic number.

It is not a de Polignac number, because 536992697741 - 26 = 536992697677 is a prime.

It is a super-2 number, since 2×5369926977412 (a number of 24 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (536992697771) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 268496348870 + 268496348871.

It is an arithmetic number, because the mean of its divisors is an integer number (268496348871).

Almost surely, 2536992697741 is an apocalyptic number.

It is an amenable number.

536992697741 is a deficient number, since it is larger than the sum of its proper divisors (1).

536992697741 is an equidigital number, since it uses as much as digits as its factorization.

536992697741 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 154314720, while the sum is 68.

The spelling of 536992697741 in words is "five hundred thirty-six billion, nine hundred ninety-two million, six hundred ninety-seven thousand, seven hundred forty-one".