Base | Representation |
---|---|
bin | 1100110011100… |
… | …0000101101101 |
3 | 10202001121022111 |
4 | 3030320011231 |
5 | 102222111432 |
6 | 5155044021 |
7 | 1221334342 |
oct | 314700555 |
9 | 122047274 |
10 | 53707117 |
11 | 28352a52 |
12 | 15ba0611 |
13 | b185879 |
14 | 71c07c9 |
15 | 4aad347 |
hex | 333816d |
53707117 has 2 divisors, whose sum is σ = 53707118. Its totient is φ = 53707116.
The previous prime is 53707111. The next prime is 53707127. The reversal of 53707117 is 71170735.
53707117 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 53494596 + 212521 = 7314^2 + 461^2 .
It is a cyclic number.
It is not a de Polignac number, because 53707117 - 215 = 53674349 is a prime.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53707111) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26853558 + 26853559.
It is an arithmetic number, because the mean of its divisors is an integer number (26853559).
Almost surely, 253707117 is an apocalyptic number.
It is an amenable number.
53707117 is a deficient number, since it is larger than the sum of its proper divisors (1).
53707117 is an equidigital number, since it uses as much as digits as its factorization.
53707117 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5145, while the sum is 31.
The square root of 53707117 is about 7328.5139694211. The cubic root of 53707117 is about 377.2917249428.
It can be divided in two parts, 53707 and 117, that added together give a square (53824 = 2322).
The spelling of 53707117 in words is "fifty-three million, seven hundred seven thousand, one hundred seventeen".
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