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53711210207381 is a prime number
BaseRepresentation
bin11000011011001100111011…
…00110101101100010010101
321001011202000120220110212212
430031212131212231202111
524020001024303114011
6310122331143523205
714212335600614126
oct1415463546554225
9231152016813785
1053711210207381
1116128883a06161
126035713759505
1323c7c3a0367cc
14d398ca59404d
156322426be08b
hex30d99d9ad895

53711210207381 has 2 divisors, whose sum is σ = 53711210207382. Its totient is φ = 53711210207380.

The previous prime is 53711210207371. The next prime is 53711210207449. The reversal of 53711210207381 is 18370201211735.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 42416173072900 + 11295037134481 = 6512770^2 + 3360809^2 .

It is a cyclic number.

It is not a de Polignac number, because 53711210207381 - 234 = 53694030338197 is a prime.

It is a super-2 number, since 2×537112102073812 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (53711210207311) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26855605103690 + 26855605103691.

It is an arithmetic number, because the mean of its divisors is an integer number (26855605103691).

Almost surely, 253711210207381 is an apocalyptic number.

It is an amenable number.

53711210207381 is a deficient number, since it is larger than the sum of its proper divisors (1).

53711210207381 is an equidigital number, since it uses as much as digits as its factorization.

53711210207381 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 70560, while the sum is 41.

The spelling of 53711210207381 in words is "fifty-three trillion, seven hundred eleven billion, two hundred ten million, two hundred seven thousand, three hundred eighty-one".