Base | Representation |
---|---|
bin | 11000011011010001010100… |
… | …11100111010001011111011 |
3 | 21001011222010021100012221202 |
4 | 30031220222130322023323 |
5 | 24020020344221201321 |
6 | 310123401435324415 |
7 | 14212451263132004 |
oct | 1415505234721373 |
9 | 231158107305852 |
10 | 53713573225211 |
11 | 16129886859459 |
12 | 6036072bb070b |
13 | 23c8225774403 |
14 | d39a723481ab |
15 | 63232ed8c70b |
hex | 30da2a73a2fb |
53713573225211 has 2 divisors, whose sum is σ = 53713573225212. Its totient is φ = 53713573225210.
The previous prime is 53713573225189. The next prime is 53713573225217. The reversal of 53713573225211 is 11252237531735.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-53713573225211 is a prime.
It is not a weakly prime, because it can be changed into another prime (53713573225217) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26856786612605 + 26856786612606.
It is an arithmetic number, because the mean of its divisors is an integer number (26856786612606).
Almost surely, 253713573225211 is an apocalyptic number.
53713573225211 is a deficient number, since it is larger than the sum of its proper divisors (1).
53713573225211 is an equidigital number, since it uses as much as digits as its factorization.
53713573225211 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1323000, while the sum is 47.
The spelling of 53713573225211 in words is "fifty-three trillion, seven hundred thirteen billion, five hundred seventy-three million, two hundred twenty-five thousand, two hundred eleven".
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