Base | Representation |
---|---|
bin | 110010000001101010… |
… | …111101110101000001 |
3 | 12010122111111102020201 |
4 | 302001222331311001 |
5 | 1340002033203323 |
6 | 40402033405201 |
7 | 3611053041355 |
oct | 620152756501 |
9 | 163574442221 |
10 | 53715131713 |
11 | 20864878541 |
12 | a4b1109801 |
13 | 50b0660c09 |
14 | 2857ccd465 |
15 | 15e5ae98ad |
hex | c81abdd41 |
53715131713 has 2 divisors, whose sum is σ = 53715131714. Its totient is φ = 53715131712.
The previous prime is 53715131689. The next prime is 53715131777. The reversal of 53715131713 is 31713151735.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 28558634049 + 25156497664 = 168993^2 + 158608^2 .
It is a cyclic number.
It is not a de Polignac number, because 53715131713 - 213 = 53715123521 is a prime.
It is not a weakly prime, because it can be changed into another prime (53715135713) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26857565856 + 26857565857.
It is an arithmetic number, because the mean of its divisors is an integer number (26857565857).
Almost surely, 253715131713 is an apocalyptic number.
It is an amenable number.
53715131713 is a deficient number, since it is larger than the sum of its proper divisors (1).
53715131713 is an equidigital number, since it uses as much as digits as its factorization.
53715131713 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 33075, while the sum is 37.
The spelling of 53715131713 in words is "fifty-three billion, seven hundred fifteen million, one hundred thirty-one thousand, seven hundred thirteen".
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