Base | Representation |
---|---|
bin | 110010000001101010… |
… | …111101110100101001 |
3 | 12010122111111102012211 |
4 | 302001222331310221 |
5 | 1340002033203224 |
6 | 40402033405121 |
7 | 3611053041322 |
oct | 620152756451 |
9 | 163574442184 |
10 | 53715131689 |
11 | 2086487851a |
12 | a4b11097a1 |
13 | 50b0660bbb |
14 | 2857ccd449 |
15 | 15e5ae9894 |
hex | c81abdd29 |
53715131689 has 2 divisors, whose sum is σ = 53715131690. Its totient is φ = 53715131688.
The previous prime is 53715131647. The next prime is 53715131713. The reversal of 53715131689 is 98613151735.
It is a happy number.
53715131689 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 42633990400 + 11081141289 = 206480^2 + 105267^2 .
It is a cyclic number.
It is not a de Polignac number, because 53715131689 - 211 = 53715129641 is a prime.
It is a super-2 number, since 2×537151316892 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (53715131609) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26857565844 + 26857565845.
It is an arithmetic number, because the mean of its divisors is an integer number (26857565845).
Almost surely, 253715131689 is an apocalyptic number.
It is an amenable number.
53715131689 is a deficient number, since it is larger than the sum of its proper divisors (1).
53715131689 is an equidigital number, since it uses as much as digits as its factorization.
53715131689 is an evil number, because the sum of its binary digits is even.
The product of its digits is 680400, while the sum is 49.
The spelling of 53715131689 in words is "fifty-three billion, seven hundred fifteen million, one hundred thirty-one thousand, six hundred eighty-nine".
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