Base | Representation |
---|---|
bin | 110010000010100010… |
… | …100011000000001101 |
3 | 12010200111220122210022 |
4 | 302002202203000031 |
5 | 1340014300430101 |
6 | 40403313551525 |
7 | 3611320634141 |
oct | 620242430015 |
9 | 163614818708 |
10 | 53729701901 |
11 | 2087201a317 |
12 | a4b5b755a5 |
13 | 50b3692a25 |
14 | 2859c03221 |
15 | 15e7026a1b |
hex | c828a300d |
53729701901 has 2 divisors, whose sum is σ = 53729701902. Its totient is φ = 53729701900.
The previous prime is 53729701897. The next prime is 53729701937. The reversal of 53729701901 is 10910792735.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 49020174025 + 4709527876 = 221405^2 + 68626^2 .
It is a cyclic number.
It is not a de Polignac number, because 53729701901 - 22 = 53729701897 is a prime.
It is a super-3 number, since 3×537297019013 (a number of 33 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53729700901) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26864850950 + 26864850951.
It is an arithmetic number, because the mean of its divisors is an integer number (26864850951).
Almost surely, 253729701901 is an apocalyptic number.
It is an amenable number.
53729701901 is a deficient number, since it is larger than the sum of its proper divisors (1).
53729701901 is an equidigital number, since it uses as much as digits as its factorization.
53729701901 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 119070, while the sum is 44.
The spelling of 53729701901 in words is "fifty-three billion, seven hundred twenty-nine million, seven hundred one thousand, nine hundred one".
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