Base | Representation |
---|---|
bin | 110010000010111100… |
… | …100111110000110001 |
3 | 12010200222202220222012 |
4 | 302002330213300301 |
5 | 1340023023142022 |
6 | 40404120252305 |
7 | 3611433013013 |
oct | 620274476061 |
9 | 163628686865 |
10 | 53736537137 |
11 | 20875968778 |
12 | a4b8311095 |
13 | 50b4c16c4a |
14 | 285aaa21b3 |
15 | 15e7926de2 |
hex | c82f27c31 |
53736537137 has 2 divisors, whose sum is σ = 53736537138. Its totient is φ = 53736537136.
The previous prime is 53736537133. The next prime is 53736537139. The reversal of 53736537137 is 73173563735.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 42571656241 + 11164880896 = 206329^2 + 105664^2 .
It is a cyclic number.
It is not a de Polignac number, because 53736537137 - 22 = 53736537133 is a prime.
Together with 53736537139, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (53736537133) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26868268568 + 26868268569.
It is an arithmetic number, because the mean of its divisors is an integer number (26868268569).
Almost surely, 253736537137 is an apocalyptic number.
It is an amenable number.
53736537137 is a deficient number, since it is larger than the sum of its proper divisors (1).
53736537137 is an equidigital number, since it uses as much as digits as its factorization.
53736537137 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 4167450, while the sum is 50.
The spelling of 53736537137 in words is "fifty-three billion, seven hundred thirty-six million, five hundred thirty-seven thousand, one hundred thirty-seven".
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