Base | Representation |
---|---|
bin | 100111000110011101001… |
… | …1001110010010011000001 |
3 | 201000202012011211222100000 |
4 | 1032030322121302103001 |
5 | 1201021404341103231 |
6 | 15232435113550213 |
7 | 1063154221451235 |
oct | 116147231622301 |
9 | 21022164758300 |
10 | 5373983925441 |
11 | 179210390aa9a |
12 | 729620415369 |
13 | 2cc9c2821441 |
14 | 14816066c5c5 |
15 | 94bca13d6e6 |
hex | 4e33a6724c1 |
5373983925441 has 48 divisors (see below), whose sum is σ = 8080093816704. Its totient is φ = 3569244839424.
The previous prime is 5373983925419. The next prime is 5373983925481. The reversal of 5373983925441 is 1445293893735.
5373983925441 is a `hidden beast` number, since 5 + 3 + 7 + 3 + 9 + 83 + 9 + 2 + 544 + 1 = 666.
It is not a de Polignac number, because 5373983925441 - 226 = 5373916816577 is a prime.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (5373983925481) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 95787100 + ... + 95843186.
It is an arithmetic number, because the mean of its divisors is an integer number (168335287848).
Almost surely, 25373983925441 is an apocalyptic number.
It is an amenable number.
5373983925441 is a deficient number, since it is larger than the sum of its proper divisors (2706109891263).
5373983925441 is a wasteful number, since it uses less digits than its factorization.
5373983925441 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 57572 (or 57560 counting only the distinct ones).
The product of its digits is 97977600, while the sum is 63.
The spelling of 5373983925441 in words is "five trillion, three hundred seventy-three billion, nine hundred eighty-three million, nine hundred twenty-five thousand, four hundred forty-one".
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