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53741574127453 is a prime number
BaseRepresentation
bin11000011100000101011110…
…11011110111111101011101
321001021122101200222102202011
430032002233123313331131
524021000220434034303
6310144312140031221
714214462206644342
oct1416025733677535
9231248350872664
1053741574127453
111613a745611783
12603b588532511
1323caa68919a14
14d3b16b0907c9
15632e1d23116d
hex30e0af6f7f5d

53741574127453 has 2 divisors, whose sum is σ = 53741574127454. Its totient is φ = 53741574127452.

The previous prime is 53741574127433. The next prime is 53741574127499. The reversal of 53741574127453 is 35472147514735.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 50082839147929 + 3658734979524 = 7076923^2 + 1912782^2 .

It is a cyclic number.

It is not a de Polignac number, because 53741574127453 - 29 = 53741574126941 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (53741574127433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26870787063726 + 26870787063727.

It is an arithmetic number, because the mean of its divisors is an integer number (26870787063727).

Almost surely, 253741574127453 is an apocalyptic number.

It is an amenable number.

53741574127453 is a deficient number, since it is larger than the sum of its proper divisors (1).

53741574127453 is an equidigital number, since it uses as much as digits as its factorization.

53741574127453 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 49392000, while the sum is 58.

The spelling of 53741574127453 in words is "fifty-three trillion, seven hundred forty-one billion, five hundred seventy-four million, one hundred twenty-seven thousand, four hundred fifty-three".