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53744775044773 is a prime number
BaseRepresentation
bin11000011100001011011100…
…01110011001111010100101
321001021221122210001212211111
430032011232032121322211
524021023244402413043
6310150001522505021
714214634425204661
oct1416055616317245
9231257583055744
1053744775044773
111614103843129a
126040120505171
1323cb158b19c37
14d3b3922378a1
1563305926109d
hex30e16e399ea5

53744775044773 has 2 divisors, whose sum is σ = 53744775044774. Its totient is φ = 53744775044772.

The previous prime is 53744775044711. The next prime is 53744775044783. The reversal of 53744775044773 is 37744057744735.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 53742124133604 + 2650911169 = 7330902^2 + 51487^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-53744775044773 is a prime.

It is a super-2 number, since 2×537447750447732 (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 53744775044699 and 53744775044708.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (53744775044783) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26872387522386 + 26872387522387.

It is an arithmetic number, because the mean of its divisors is an integer number (26872387522387).

Almost surely, 253744775044773 is an apocalyptic number.

It is an amenable number.

53744775044773 is a deficient number, since it is larger than the sum of its proper divisors (1).

53744775044773 is an equidigital number, since it uses as much as digits as its factorization.

53744775044773 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 968083200, while the sum is 67.

The spelling of 53744775044773 in words is "fifty-three trillion, seven hundred forty-four billion, seven hundred seventy-five million, forty-four thousand, seven hundred seventy-three".