Base | Representation |
---|---|
bin | 100111000110110101011… |
… | …0011001111100101111111 |
3 | 201000211021202201211110002 |
4 | 1032031222303033211333 |
5 | 1201030040222433112 |
6 | 15233051441304515 |
7 | 1063213311251615 |
oct | 116155263174577 |
9 | 21024252654402 |
10 | 5374795905407 |
11 | 1792490193615 |
12 | 72980833513b |
13 | 2ccac1b0a166 |
14 | 1481da4356b5 |
15 | 94c265801c2 |
hex | 4e36accf97f |
5374795905407 has 2 divisors, whose sum is σ = 5374795905408. Its totient is φ = 5374795905406.
The previous prime is 5374795905371. The next prime is 5374795905439. The reversal of 5374795905407 is 7045095974735.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5374795905407 - 210 = 5374795904383 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5374795905497) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2687397952703 + 2687397952704.
It is an arithmetic number, because the mean of its divisors is an integer number (2687397952704).
Almost surely, 25374795905407 is an apocalyptic number.
5374795905407 is a deficient number, since it is larger than the sum of its proper divisors (1).
5374795905407 is an equidigital number, since it uses as much as digits as its factorization.
5374795905407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 166698000, while the sum is 65.
The spelling of 5374795905407 in words is "five trillion, three hundred seventy-four billion, seven hundred ninety-five million, nine hundred five thousand, four hundred seven".
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