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53754217030453 is a prime number
BaseRepresentation
bin11000011100011101000010…
…00000101110001100110101
321001022212000210211110012211
430032032201000232030311
524021202114024433303
6310154202453213421
714215420415566012
oct1416164100561465
9231285023743184
1053754217030453
1116145043164945
126041b16631271
1323cc00201c104
14d3ba0a222709
1563340d14666d
hex30e3a102e335

53754217030453 has 2 divisors, whose sum is σ = 53754217030454. Its totient is φ = 53754217030452.

The previous prime is 53754217030439. The next prime is 53754217030541. The reversal of 53754217030453 is 35403071245735.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 53412812877649 + 341404152804 = 7308407^2 + 584298^2 .

It is a cyclic number.

It is not a de Polignac number, because 53754217030453 - 217 = 53754216899381 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 53754217030397 and 53754217030406.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (53754217033453) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26877108515226 + 26877108515227.

It is an arithmetic number, because the mean of its divisors is an integer number (26877108515227).

Almost surely, 253754217030453 is an apocalyptic number.

It is an amenable number.

53754217030453 is a deficient number, since it is larger than the sum of its proper divisors (1).

53754217030453 is an equidigital number, since it uses as much as digits as its factorization.

53754217030453 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5292000, while the sum is 49.

The spelling of 53754217030453 in words is "fifty-three trillion, seven hundred fifty-four billion, two hundred seventeen million, thirty thousand, four hundred fifty-three".