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53765720033317 is a prime number
BaseRepresentation
bin11000011100110010011101…
…01001001100100000100101
321001100221201110202112122221
430032121032221030200211
524021344143312031232
6310203344130352341
714216305443523345
oct1416311651144045
9231327643675587
1053765720033317
1116149a06320186
1260441a6a2b6b1
132400116210596
14d3c3bbc2ad25
15633882e43897
hex30e64ea4c825

53765720033317 has 2 divisors, whose sum is σ = 53765720033318. Its totient is φ = 53765720033316.

The previous prime is 53765720033269. The next prime is 53765720033341. The reversal of 53765720033317 is 71333002756735.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 45822082178401 + 7943637854916 = 6769201^2 + 2818446^2 .

It is a cyclic number.

It is not a de Polignac number, because 53765720033317 - 227 = 53765585815589 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (53765720033387) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26882860016658 + 26882860016659.

It is an arithmetic number, because the mean of its divisors is an integer number (26882860016659).

Almost surely, 253765720033317 is an apocalyptic number.

It is an amenable number.

53765720033317 is a deficient number, since it is larger than the sum of its proper divisors (1).

53765720033317 is an equidigital number, since it uses as much as digits as its factorization.

53765720033317 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8334900, while the sum is 52.

The spelling of 53765720033317 in words is "fifty-three trillion, seven hundred sixty-five billion, seven hundred twenty million, thirty-three thousand, three hundred seventeen".