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5377014437 is a prime number
BaseRepresentation
bin1010000000111111…
…01011101010100101
3111212201210122010212
411000133223222211
542003003430222
62245320025205
7250150603634
oct50037535245
914781718125
105377014437
11230a203593
121060902205
13678cb2b62
143901a151b
152170c96e2
hex1407ebaa5

5377014437 has 2 divisors, whose sum is σ = 5377014438. Its totient is φ = 5377014436.

The previous prime is 5377014407. The next prime is 5377014457. The reversal of 5377014437 is 7344107735.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4405507876 + 971506561 = 66374^2 + 31169^2 .

It is a cyclic number.

It is not a de Polignac number, because 5377014437 - 210 = 5377013413 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 5377014394 and 5377014403.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5377014407) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2688507218 + 2688507219.

It is an arithmetic number, because the mean of its divisors is an integer number (2688507219).

Almost surely, 25377014437 is an apocalyptic number.

It is an amenable number.

5377014437 is a deficient number, since it is larger than the sum of its proper divisors (1).

5377014437 is an equidigital number, since it uses as much as digits as its factorization.

5377014437 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 246960, while the sum is 41.

The square root of 5377014437 is about 73328.1285524184. The cubic root of 5377014437 is about 1751.9178361844.

The spelling of 5377014437 in words is "five billion, three hundred seventy-seven million, fourteen thousand, four hundred thirty-seven".