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5377113403 is a prime number
BaseRepresentation
bin1010000001000000…
…00011110100111011
3111212201222122220021
411000200003310323
542003020112103
62245322111311
7250151465314
oct50040036473
914781878807
105377113403
11230a270982
12106094b537
13679018c0c
143901c960b
152170e8bbd
hex140803d3b

5377113403 has 2 divisors, whose sum is σ = 5377113404. Its totient is φ = 5377113402.

The previous prime is 5377113389. The next prime is 5377113419. The reversal of 5377113403 is 3043117735.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 5377113403 - 213 = 5377105211 is a prime.

It is not a weakly prime, because it can be changed into another prime (5377113803) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2688556701 + 2688556702.

It is an arithmetic number, because the mean of its divisors is an integer number (2688556702).

Almost surely, 25377113403 is an apocalyptic number.

5377113403 is a deficient number, since it is larger than the sum of its proper divisors (1).

5377113403 is an equidigital number, since it uses as much as digits as its factorization.

5377113403 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 26460, while the sum is 34.

The square root of 5377113403 is about 73328.8033653898. The cubic root of 5377113403 is about 1751.9285843569.

The spelling of 5377113403 in words is "five billion, three hundred seventy-seven million, one hundred thirteen thousand, four hundred three".