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5378543394281 is a prime number
BaseRepresentation
bin100111001000100101000…
…1010110001110111101001
3201001011221221021222202022
41032101022022301313221
51201110224102104111
615234511351114225
71063405214344301
oct116211212616751
921034857258668
105378543394281
111794033589462
1272a493372975
1330026b31a1b5
14148474018601
1594d955772db
hex4e44a2b1de9

5378543394281 has 2 divisors, whose sum is σ = 5378543394282. Its totient is φ = 5378543394280.

The previous prime is 5378543394253. The next prime is 5378543394283. The reversal of 5378543394281 is 1824933458735.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3448111034281 + 1930432360000 = 1856909^2 + 1389400^2 .

It is a cyclic number.

It is not a de Polignac number, because 5378543394281 - 226 = 5378476285417 is a prime.

It is a super-2 number, since 2×53785433942812 (a number of 26 digits) contains 22 as substring.

Together with 5378543394283, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (5378543394283) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2689271697140 + 2689271697141.

It is an arithmetic number, because the mean of its divisors is an integer number (2689271697141).

Almost surely, 25378543394281 is an apocalyptic number.

It is an amenable number.

5378543394281 is a deficient number, since it is larger than the sum of its proper divisors (1).

5378543394281 is an equidigital number, since it uses as much as digits as its factorization.

5378543394281 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 87091200, while the sum is 62.

The spelling of 5378543394281 in words is "five trillion, three hundred seventy-eight billion, five hundred forty-three million, three hundred ninety-four thousand, two hundred eighty-one".