Base | Representation |
---|---|
bin | 110010001001001001… |
… | …101000010110001101 |
3 | 12010222020121102001122 |
4 | 302021021220112031 |
5 | 1340231144020301 |
6 | 40422315050325 |
7 | 3614135432333 |
oct | 621111502615 |
9 | 163866542048 |
10 | 53840610701 |
11 | 20919691789 |
12 | a5271409a5 |
13 | 5100655937 |
14 | 286a833b53 |
15 | 1601b3381b |
hex | c8926858d |
53840610701 has 2 divisors, whose sum is σ = 53840610702. Its totient is φ = 53840610700.
The previous prime is 53840610679. The next prime is 53840610721. The reversal of 53840610701 is 10701604835.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 33434488201 + 20406122500 = 182851^2 + 142850^2 .
It is a cyclic number.
It is not a de Polignac number, because 53840610701 - 214 = 53840594317 is a prime.
It is a super-2 number, since 2×538406107012 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53840610721) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26920305350 + 26920305351.
It is an arithmetic number, because the mean of its divisors is an integer number (26920305351).
Almost surely, 253840610701 is an apocalyptic number.
It is an amenable number.
53840610701 is a deficient number, since it is larger than the sum of its proper divisors (1).
53840610701 is an equidigital number, since it uses as much as digits as its factorization.
53840610701 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 20160, while the sum is 35.
The spelling of 53840610701 in words is "fifty-three billion, eight hundred forty million, six hundred ten thousand, seven hundred one".
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