Base | Representation |
---|---|
bin | 100000000101111… |
… | …110001101111001 |
3 | 1101112011101222121 |
4 | 200011332031321 |
5 | 2100314431343 |
6 | 125232321241 |
7 | 16225430431 |
oct | 4005761571 |
9 | 1345141877 |
10 | 538436473 |
11 | 256a2a323 |
12 | 1303a3221 |
13 | 87722083 |
14 | 5171d2c1 |
15 | 3240baed |
hex | 2017e379 |
538436473 has 2 divisors, whose sum is σ = 538436474. Its totient is φ = 538436472.
The previous prime is 538436471. The next prime is 538436491. The reversal of 538436473 is 374634835.
538436473 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 354644224 + 183792249 = 18832^2 + 13557^2 .
It is a cyclic number.
It is not a de Polignac number, because 538436473 - 21 = 538436471 is a prime.
Together with 538436471, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (538436471) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 269218236 + 269218237.
It is an arithmetic number, because the mean of its divisors is an integer number (269218237).
Almost surely, 2538436473 is an apocalyptic number.
It is an amenable number.
538436473 is a deficient number, since it is larger than the sum of its proper divisors (1).
538436473 is an equidigital number, since it uses as much as digits as its factorization.
538436473 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 725760, while the sum is 43.
The square root of 538436473 is about 23204.2339455540. The cubic root of 538436473 is about 813.5385872096.
The spelling of 538436473 in words is "five hundred thirty-eight million, four hundred thirty-six thousand, four hundred seventy-three".
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