Base | Representation |
---|---|
bin | 110010001001100010… |
… | …000001101101100101 |
3 | 12010222200122022211112 |
4 | 302021202001231211 |
5 | 1340234313143203 |
6 | 40423104114405 |
7 | 3614243666561 |
oct | 621142015545 |
9 | 163880568745 |
10 | 53847006053 |
11 | 2092225a6a5 |
12 | a529305a05 |
13 | 5101a84879 |
14 | 286b61a6a1 |
15 | 16024986d8 |
hex | c89881b65 |
53847006053 has 2 divisors, whose sum is σ = 53847006054. Its totient is φ = 53847006052.
The previous prime is 53847006023. The next prime is 53847006061. The reversal of 53847006053 is 35060074835.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 51816782689 + 2030223364 = 227633^2 + 45058^2 .
It is a cyclic number.
It is not a de Polignac number, because 53847006053 - 226 = 53779897189 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 53847006053.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53847006023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26923503026 + 26923503027.
It is an arithmetic number, because the mean of its divisors is an integer number (26923503027).
Almost surely, 253847006053 is an apocalyptic number.
It is an amenable number.
53847006053 is a deficient number, since it is larger than the sum of its proper divisors (1).
53847006053 is an equidigital number, since it uses as much as digits as its factorization.
53847006053 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 302400, while the sum is 41.
The spelling of 53847006053 in words is "fifty-three billion, eight hundred forty-seven million, six thousand, fifty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •