Search a number
-
+
5385006809957 is a prime number
BaseRepresentation
bin100111001011100101101…
…1010110000001101100101
3201001210122101100112020002
41032113023122300031211
51201211443220404312
615241501000351045
71064024326435625
oct116271332601545
921053571315202
105385006809957
11179684aa59305
1272b797a75485
13300a5b3cc108
141488c85b8885
1595122bed4c2
hex4e5cb6b0365

5385006809957 has 2 divisors, whose sum is σ = 5385006809958. Its totient is φ = 5385006809956.

The previous prime is 5385006809947. The next prime is 5385006809989. The reversal of 5385006809957 is 7599086005835.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 4476719662276 + 908287147681 = 2115826^2 + 953041^2 .

It is a cyclic number.

It is not a de Polignac number, because 5385006809957 - 230 = 5383933068133 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 5385006809893 and 5385006809902.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5385006809947) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2692503404978 + 2692503404979.

It is an arithmetic number, because the mean of its divisors is an integer number (2692503404979).

Almost surely, 25385006809957 is an apocalyptic number.

It is an amenable number.

5385006809957 is a deficient number, since it is larger than the sum of its proper divisors (1).

5385006809957 is an equidigital number, since it uses as much as digits as its factorization.

5385006809957 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 81648000, while the sum is 65.

The spelling of 5385006809957 in words is "five trillion, three hundred eighty-five billion, six million, eight hundred nine thousand, nine hundred fifty-seven".