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53853552033517 is a prime number
BaseRepresentation
bin11000011111010110000011…
…10101101011111011101101
321001200100102122011110011101
430033223001311223323231
524024314033310033032
6310311551423123101
714225535136306645
oct1417530165537355
9231610378143141
1053853552033517
11161831881889a5
126059219743491
1324084a2b26732
14d42750c1b525
15635cc3cc4de7
hex30fac1d6beed

53853552033517 has 2 divisors, whose sum is σ = 53853552033518. Its totient is φ = 53853552033516.

The previous prime is 53853552033487. The next prime is 53853552033527. The reversal of 53853552033517 is 71533025535835.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 43829020881801 + 10024531151716 = 6620349^2 + 3166154^2 .

It is a cyclic number.

It is not a de Polignac number, because 53853552033517 - 215 = 53853552000749 is a prime.

It is a super-3 number, since 3×538535520335173 (a number of 42 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (53853552033527) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26926776016758 + 26926776016759.

It is an arithmetic number, because the mean of its divisors is an integer number (26926776016759).

Almost surely, 253853552033517 is an apocalyptic number.

It is an amenable number.

53853552033517 is a deficient number, since it is larger than the sum of its proper divisors (1).

53853552033517 is an equidigital number, since it uses as much as digits as its factorization.

53853552033517 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 28350000, while the sum is 55.

The spelling of 53853552033517 in words is "fifty-three trillion, eight hundred fifty-three billion, five hundred fifty-two million, thirty-three thousand, five hundred seventeen".