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53868670188373 is a prime number
BaseRepresentation
bin11000011111110010001101…
…11100110111101101010101
321001201210110020122021211201
430033321012330313231111
524030041014032011443
6310322531521432501
714226611602434115
oct1417710674675525
9231653406567751
1053868670188373
1116189635a71457
12606013879b731
132409a41ca18b1
14d433869db045
156363ab17834d
hex30fe46f37b55

53868670188373 has 2 divisors, whose sum is σ = 53868670188374. Its totient is φ = 53868670188372.

The previous prime is 53868670188331. The next prime is 53868670188413. The reversal of 53868670188373 is 37388107686835.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 30894843405969 + 22973826782404 = 5558313^2 + 4793102^2 .

It is a cyclic number.

It is not a de Polignac number, because 53868670188373 - 229 = 53868133317461 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 53868670188296 and 53868670188305.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (53868670188173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26934335094186 + 26934335094187.

It is an arithmetic number, because the mean of its divisors is an integer number (26934335094187).

Almost surely, 253868670188373 is an apocalyptic number.

It is an amenable number.

53868670188373 is a deficient number, since it is larger than the sum of its proper divisors (1).

53868670188373 is an equidigital number, since it uses as much as digits as its factorization.

53868670188373 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 975421440, while the sum is 73.

The spelling of 53868670188373 in words is "fifty-three trillion, eight hundred sixty-eight billion, six hundred seventy million, one hundred eighty-eight thousand, three hundred seventy-three".