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538855501 is a prime number
BaseRepresentation
bin100000000111100…
…100100001001101
31101112221200210011
4200013210201031
52100421334001
6125245313221
716232124202
oct4007444115
91345850704
10538855501
11257196128
12130565811
138783aa12
14517cbca9
1532490d51
hex201e484d

538855501 has 2 divisors, whose sum is σ = 538855502. Its totient is φ = 538855500.

The previous prime is 538855487. The next prime is 538855507. The reversal of 538855501 is 105558835.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 462293001 + 76562500 = 21501^2 + 8750^2 .

It is a cyclic number.

It is not a de Polignac number, because 538855501 - 25 = 538855469 is a prime.

It is a super-3 number, since 3×5388555013 (a number of 27 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (538855507) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 269427750 + 269427751.

It is an arithmetic number, because the mean of its divisors is an integer number (269427751).

Almost surely, 2538855501 is an apocalyptic number.

It is an amenable number.

538855501 is a deficient number, since it is larger than the sum of its proper divisors (1).

538855501 is an equidigital number, since it uses as much as digits as its factorization.

538855501 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 120000, while the sum is 40.

The square root of 538855501 is about 23213.2613176176. The cubic root of 538855501 is about 813.7495728260.

The spelling of 538855501 in words is "five hundred thirty-eight million, eight hundred fifty-five thousand, five hundred one".