Base | Representation |
---|---|
bin | 110010001110111011… |
… | …101100010111011111 |
3 | 12011020000011000102012 |
4 | 302032323230113133 |
5 | 1340431012323242 |
6 | 40440102221435 |
7 | 3616424131514 |
oct | 621673542737 |
9 | 164200130365 |
10 | 53937620447 |
11 | 20969420627 |
12 | a55372487b |
13 | 5117790359 |
14 | 287968730b |
15 | 160a3e7282 |
hex | c8eeec5df |
53937620447 has 2 divisors, whose sum is σ = 53937620448. Its totient is φ = 53937620446.
The previous prime is 53937620423. The next prime is 53937620453. The reversal of 53937620447 is 74402673935.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-53937620447 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 53937620395 and 53937620404.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53937628447) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26968810223 + 26968810224.
It is an arithmetic number, because the mean of its divisors is an integer number (26968810224).
Almost surely, 253937620447 is an apocalyptic number.
53937620447 is a deficient number, since it is larger than the sum of its proper divisors (1).
53937620447 is an equidigital number, since it uses as much as digits as its factorization.
53937620447 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3810240, while the sum is 50.
The spelling of 53937620447 in words is "fifty-three billion, nine hundred thirty-seven million, six hundred twenty thousand, four hundred forty-seven".
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