Base | Representation |
---|---|
bin | 100111010000000101001… |
… | …0110011000110110101101 |
3 | 201002201112121112122111111 |
4 | 1032200022112120312231 |
5 | 1201341222024034114 |
6 | 15250134050352021 |
7 | 1064515343133316 |
oct | 116401226306655 |
9 | 21081477478444 |
10 | 5394652564909 |
11 | 179a94a809813 |
12 | 73162a28b611 |
13 | 3019378a811a |
14 | 14916168760d |
15 | 954d9934bc4 |
hex | 4e80a598dad |
5394652564909 has 2 divisors, whose sum is σ = 5394652564910. Its totient is φ = 5394652564908.
The previous prime is 5394652564883. The next prime is 5394652564913. The reversal of 5394652564909 is 9094652564935.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4228637013225 + 1166015551684 = 2056365^2 + 1079822^2 .
It is a cyclic number.
It is not a de Polignac number, because 5394652564909 - 231 = 5392505081261 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5394652564979) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2697326282454 + 2697326282455.
It is an arithmetic number, because the mean of its divisors is an integer number (2697326282455).
Almost surely, 25394652564909 is an apocalyptic number.
It is an amenable number.
5394652564909 is a deficient number, since it is larger than the sum of its proper divisors (1).
5394652564909 is an equidigital number, since it uses as much as digits as its factorization.
5394652564909 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 314928000, while the sum is 67.
The spelling of 5394652564909 in words is "five trillion, three hundred ninety-four billion, six hundred fifty-two million, five hundred sixty-four thousand, nine hundred nine".
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