Base | Representation |
---|---|
bin | 1111101100111101111… |
… | …11100000011100110001 |
3 | 1220120122100121111212102 |
4 | 13312132333200130301 |
5 | 32314433310010423 |
6 | 1051505511310145 |
7 | 53660156251304 |
oct | 7663677403461 |
9 | 1816570544772 |
10 | 539538360113 |
11 | 1988a937a675 |
12 | 8869637b355 |
13 | 3bb5568952c |
14 | 1c184382b3b |
15 | e07bd2cc28 |
hex | 7d9efe0731 |
539538360113 has 2 divisors, whose sum is σ = 539538360114. Its totient is φ = 539538360112.
The previous prime is 539538360103. The next prime is 539538360139. The reversal of 539538360113 is 311063835935.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 367651833649 + 171886526464 = 606343^2 + 414592^2 .
It is a cyclic number.
It is not a de Polignac number, because 539538360113 - 228 = 539269924657 is a prime.
It is a super-2 number, since 2×5395383601132 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (539538360103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 269769180056 + 269769180057.
It is an arithmetic number, because the mean of its divisors is an integer number (269769180057).
Almost surely, 2539538360113 is an apocalyptic number.
It is an amenable number.
539538360113 is a deficient number, since it is larger than the sum of its proper divisors (1).
539538360113 is an equidigital number, since it uses as much as digits as its factorization.
539538360113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 874800, while the sum is 47.
The spelling of 539538360113 in words is "five hundred thirty-nine billion, five hundred thirty-eight million, three hundred sixty thousand, one hundred thirteen".
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