Base | Representation |
---|---|
bin | 110010010000011011… |
… | …000011000100001101 |
3 | 12011021202011222101012 |
4 | 302100123003010031 |
5 | 1341003412221401 |
6 | 40442354055005 |
7 | 3620146451201 |
oct | 622033030415 |
9 | 164252158335 |
10 | 53962617101 |
11 | 20981543a18 |
12 | a55bb7a465 |
13 | 511ca02b83 |
14 | 287cb12b01 |
15 | 160c6d38bb |
hex | c906c310d |
53962617101 has 2 divisors, whose sum is σ = 53962617102. Its totient is φ = 53962617100.
The previous prime is 53962617091. The next prime is 53962617139. The reversal of 53962617101 is 10171626935.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 48068370025 + 5894247076 = 219245^2 + 76774^2 .
It is a cyclic number.
It is not a de Polignac number, because 53962617101 - 234 = 36782747917 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53962613101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26981308550 + 26981308551.
It is an arithmetic number, because the mean of its divisors is an integer number (26981308551).
Almost surely, 253962617101 is an apocalyptic number.
It is an amenable number.
53962617101 is a deficient number, since it is larger than the sum of its proper divisors (1).
53962617101 is an equidigital number, since it uses as much as digits as its factorization.
53962617101 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 68040, while the sum is 41.
The spelling of 53962617101 in words is "fifty-three billion, nine hundred sixty-two million, six hundred seventeen thousand, one hundred one".
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