Base | Representation |
---|---|
bin | 1100110111101… |
… | …0110000100001 |
3 | 10202120110220102 |
4 | 3031322300201 |
5 | 102304331233 |
6 | 5204552145 |
7 | 1223552441 |
oct | 315726041 |
9 | 122513812 |
10 | 53980193 |
11 | 2851a133 |
12 | 160b2655 |
13 | b24cc57 |
14 | 7252121 |
15 | 4b141e8 |
hex | 337ac21 |
53980193 has 2 divisors, whose sum is σ = 53980194. Its totient is φ = 53980192.
The previous prime is 53980183. The next prime is 53980217. The reversal of 53980193 is 39108935.
53980193 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 51955264 + 2024929 = 7208^2 + 1423^2 .
It is a cyclic number.
It is not a de Polignac number, because 53980193 - 210 = 53979169 is a prime.
It is a super-2 number, since 2×539801932 = 5827722472634498, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (53980123) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26990096 + 26990097.
It is an arithmetic number, because the mean of its divisors is an integer number (26990097).
Almost surely, 253980193 is an apocalyptic number.
It is an amenable number.
53980193 is a deficient number, since it is larger than the sum of its proper divisors (1).
53980193 is an equidigital number, since it uses as much as digits as its factorization.
53980193 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 29160, while the sum is 38.
The square root of 53980193 is about 7347.1214090962. The cubic root of 53980193 is about 377.9300958795.
The spelling of 53980193 in words is "fifty-three million, nine hundred eighty thousand, one hundred ninety-three".
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