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53985047437 is a prime number
BaseRepresentation
bin110010010001110000…
…100111001110001101
312011100022101120000101
4302101300213032031
51341030133004222
640444514531101
73620541221566
oct622160471615
9164308346011
1053985047437
1120993174192
12a567596a91
135124557569
142881ab116d
15160e664927
hexc91c2738d

53985047437 has 2 divisors, whose sum is σ = 53985047438. Its totient is φ = 53985047436.

The previous prime is 53985047399. The next prime is 53985047443. The reversal of 53985047437 is 73474058935.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 35907976036 + 18077071401 = 189494^2 + 134451^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-53985047437 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (53985047447) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26992523718 + 26992523719.

It is an arithmetic number, because the mean of its divisors is an integer number (26992523719).

Almost surely, 253985047437 is an apocalyptic number.

It is an amenable number.

53985047437 is a deficient number, since it is larger than the sum of its proper divisors (1).

53985047437 is an equidigital number, since it uses as much as digits as its factorization.

53985047437 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12700800, while the sum is 55.

The spelling of 53985047437 in words is "fifty-three billion, nine hundred eighty-five million, forty-seven thousand, four hundred thirty-seven".