Base | Representation |
---|---|
bin | 100111010010010100101… |
… | …1010010010110110001111 |
3 | 201010011222020212010001121 |
4 | 1032210221122102312033 |
5 | 1201431102433243441 |
6 | 15252252012021411 |
7 | 1065045603155332 |
oct | 116445132226617 |
9 | 21104866763047 |
10 | 5399468649871 |
11 | 17a19a131a71a |
12 | 732553161867 |
13 | 3022245c1b3a |
14 | 14949b152619 |
15 | 956bc65cdd1 |
hex | 4e929692d8f |
5399468649871 has 2 divisors, whose sum is σ = 5399468649872. Its totient is φ = 5399468649870.
The previous prime is 5399468649863. The next prime is 5399468649877. The reversal of 5399468649871 is 1789468649935.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5399468649871 - 23 = 5399468649863 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5399468649791 and 5399468649800.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5399468649877) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2699734324935 + 2699734324936.
It is an arithmetic number, because the mean of its divisors is an integer number (2699734324936).
Almost surely, 25399468649871 is an apocalyptic number.
5399468649871 is a deficient number, since it is larger than the sum of its proper divisors (1).
5399468649871 is an equidigital number, since it uses as much as digits as its factorization.
5399468649871 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2821754880, while the sum is 79.
The spelling of 5399468649871 in words is "five trillion, three hundred ninety-nine billion, four hundred sixty-eight million, six hundred forty-nine thousand, eight hundred seventy-one".
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