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54000000023 is a prime number
BaseRepresentation
bin110010010010101001…
…101001110000010111
312011101100112020002212
4302102221221300113
51341043000000043
640450211224035
73621112266254
oct622251516027
9164340466085
1054000000023
11209a06572a2
12a5705a801b
135127691448
142883a8442b
151610b1a018
hexc92a69c17

54000000023 has 2 divisors, whose sum is σ = 54000000024. Its totient is φ = 54000000022.

The previous prime is 53999999981. The next prime is 54000000031. The reversal of 54000000023 is 32000000045.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 54000000023 - 212 = 53999995927 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 53999999944 and 54000000007.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (54000000053) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27000000011 + 27000000012.

It is an arithmetic number, because the mean of its divisors is an integer number (27000000012).

Almost surely, 254000000023 is an apocalyptic number.

54000000023 is a deficient number, since it is larger than the sum of its proper divisors (1).

54000000023 is an equidigital number, since it uses as much as digits as its factorization.

54000000023 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 120, while the sum is 14.

Adding to 54000000023 its reverse (32000000045), we get a palindrome (86000000068).

The spelling of 54000000023 in words is "fifty-four billion, twenty-three", and thus it is an aban number.